What is the derivative of y=e^x(p+psqrt(p)) ?

The derivative of y=e^x(p+psqrt(p)) is (p+p^{3/2})e^x

What is the first derivative of y=e^x(p+psqrt(p)) ?

The first derivative of y=e^x(p+psqrt(p)) is (p+p^{3/2})e^x

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derivative of

y = e^{x} (p + p p)

(p + p^{\frac{3}{2}}) e^{x}

Solution steps

\frac{d}{d x} (e^{x} (p + p p))

Simplify

e^{x} (p + p p) : e^{x} (p + p^{\frac{3}{2}})

= \frac{d}{d x} (e^{x} (p + p^{\frac{3}{2}}))

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= (p + p^{\frac{3}{2}}) \frac{d}{d x} (e^{x})

Apply the common derivative:

\frac{d}{d x} (e^{x}) = e^{x}

= (p + p^{\frac{3}{2}}) e^{x}

ln (2 - 3 x)

\frac{d y}{d x} = \frac{x sec ( \frac{y}{x} ) + y}{x}

\int sec (\frac{x}{2}) tan (\frac{x}{2}) d x

y = 2 5 - x^{2}

\int (x^{2} + 3)^{3} 2 x d x

What is the derivative of y=e^x(p+psqrt(p)) ?
The derivative of y=e^x(p+psqrt(p)) is (p+p^{3/2})e^x
What is the first derivative of y=e^x(p+psqrt(p)) ?
The first derivative of y=e^x(p+psqrt(p)) is (p+p^{3/2})e^x