What is the sum from n=0 to infinity of n/(7n+1) ?

The sum from n=0 to infinity of n/(7n+1) is diverges

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sum from n=0 to infinity of n/(7n+1)

n = 0 \sum \infty \frac{n}{7 n + 1}

diverges

Solution steps

n = 0 \sum \infty \frac{n}{7 n + 1}

Apply Series Divergence Test:

diverges

= diverges

n = 1 \sum \infty \frac{n}{n ^{2} + 2 n + 3}

n = 1 \sum \infty (n!) e^{- n}

n = 1 \sum \infty \frac{e ^{\frac{3}{n}}}{n}

n = 0 \sum \infty \frac{1}{7 + n}

k = 1 \sum \infty \frac{1}{k ^{3}}

What is the sum from n=0 to infinity of n/(7n+1) ?
The sum from n=0 to infinity of n/(7n+1) is diverges