What is derivative of f(x)=(4t-1)(3t-6)^{-1} ?

The answer to derivative of f(x)=(4t-1)(3t-6)^{-1} is (dt)/(dx)=0

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derivative of f(x)=(4t-1)(3t-6)^{-1}

derivative of

f (x) = (4 t - 1) (3 t - 6)^{- 1}

\frac{d t}{d x} = 0

Solution steps

f (x) = (4 t - 1) (3 t - 6)^{- 1}

Treat

t

t (x)

Differentiate both sides:

0 = - \frac{21 \frac{d t}{d x}}{( 3 t - 6 ) ^{2}}

Isolate

\frac{d t}{d x} : \frac{d t}{d x} = 0

\frac{d t}{d x} = 0

\int \frac{x ^{2}}{( x ^{3} - 6 ) ^{2}} d x

f (x) = \frac{1}{x ^{10}}

f (x) = x + 7, (9, 4)

\frac{d x}{d t} = \frac{2 x ^{2} + t 7 t ^{2} + x ^{2}}{2 t x}

f (x) = cos (\frac{e ^{x}}{x ^{4} + 1})

What is derivative of f(x)=(4t-1)(3t-6)^{-1} ?
The answer to derivative of f(x)=(4t-1)(3t-6)^{-1} is (dt)/(dx)=0