What is the sum from n=1 to infinity of 1/(n^{1.2)} ?

The sum from n=1 to infinity of 1/(n^{1.2)} is converges

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sum from n=1 to infinity of 1/(n^{1.2)}

n = 1 \sum \infty \frac{1}{n ^{1.2}}

converges

Solution steps

n = 1 \sum \infty \frac{1}{n ^{1.2}}

Apply p-Series Test:

converges

= converges

n = 2 \sum \infty (- 0.15)^{n}

n = 0 \sum \infty \frac{20}{4 ^{n}}

n = 1 \sum \infty (\frac{π}{3})^{n}

k = 1 \sum \infty \frac{1}{k + 1}

n = 0 \sum \infty \frac{n}{9 + n ^{2}}

What is the sum from n=1 to infinity of 1/(n^{1.2)} ?
The sum from n=1 to infinity of 1/(n^{1.2)} is converges