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Popular >

derivative of 5\sqrt[5]{x^2}-4/x+sqrt(2)

Solution

Solution

\frac{2 x ^{2} + 4 x ^{\frac{3}{5}}}{x ^{\frac{13}{5}}}

Solution steps

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

\frac{d}{d x} (\frac{4}{x}) = - \frac{4}{x ^{2}}

\frac{d}{d x} (2) = 0

= \frac{2}{x ^{\frac{3}{5}}} - (- \frac{4}{x ^{2}}) + 0

Simplify

\frac{2}{x ^{\frac{3}{5}}} - (- \frac{4}{x ^{2}}) + 0 : \frac{2 x ^{2} + 4 x ^{\frac{3}{5}}}{x ^{\frac{13}{5}}}

= \frac{2 x ^{2} + 4 x ^{\frac{3}{5}}}{x ^{\frac{13}{5}}}

Popular Examples

inverse oflaplace (24)/(s^4)inverse laplace

\frac{24}{s ^{4}}

(\partial)/(\partial x)(3-x^2+xy-3y^2)

\frac{\partial}{\partial x} (3 - x^{2} + x y - 3 y^{2})

(\partial)/(\partial y)(sqrt(2x^2-4y^3))

\frac{\partial}{\partial y} (2 x^{2} - 4 y^{3})

tangent of y= 9/(x^2+2),(1,3)tangent of

y = \frac{9}{x ^{2} + 2}, (1, 3)

d/(dy)(ln(((5y+1)^2)/(sqrt(y^2+1))))

\frac{d}{d y} (ln (\frac{( 5 y + 1 ) ^{2}}{y ^{2} + 1}))

Frequently Asked Questions (FAQ)

What is the derivative of 5\sqrt[5]{x^2}-4/x+sqrt(2) ?
The derivative of 5\sqrt[5]{x^2}-4/x+sqrt(2) is (2x^2+4x^{3/5})/(x^{13/5)}
What is the first derivative of 5\sqrt[5]{x^2}-4/x+sqrt(2) ?
The first derivative of 5\sqrt[5]{x^2}-4/x+sqrt(2) is (2x^2+4x^{3/5})/(x^{13/5)}