What is the sum from k=0 to infinity of k/(k+1) ?

The sum from k=0 to infinity of k/(k+1) is diverges

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sum from k=0 to infinity of k/(k+1)

k = 0 \sum \infty \frac{k}{k + 1}

diverges

Solution steps

k = 0 \sum \infty \frac{k}{k + 1}

Apply Series Divergence Test:

diverges

= diverges

n = 1 \sum \infty 2^{n} - n

n = 0 \sum \infty \frac{n}{n + 5}

n = 1 \sum \infty \frac{8}{n}

n = 1 \sum \infty \frac{1}{n ^{\frac{1}{5}}}

n = 0 \sum \infty \frac{n !}{7 ^{n}}

What is the sum from k=0 to infinity of k/(k+1) ?
The sum from k=0 to infinity of k/(k+1) is diverges