What is the sum from n=0 to infinity of (-5/7)^n ?

The sum from n=0 to infinity of (-5/7)^n is 7/12

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sum from n=0 to infinity of (-5/7)^n

n = 0 \sum \infty (- \frac{5}{7})^{n}

\frac{7}{12}

Solution steps

n = 0 \sum \infty (- \frac{5}{7})^{n}

Apply Series Geometric Test:

\frac{7}{12}

= \frac{7}{12}

n = 1 \sum \infty \frac{9}{n}

k = 2 \sum \infty \frac{1}{k ln ( k )}

n = 1 \sum \infty cos (\frac{π}{n})

n = 1 \sum \infty \frac{e ^{n}}{n ^{5}}

k = 3 \sum \infty \frac{1}{2 ^{k - 1}}

What is the sum from n=0 to infinity of (-5/7)^n ?
The sum from n=0 to infinity of (-5/7)^n is 7/12