What is the sum from n=1 to infinity of cos(1/(n+1)) ?

The sum from n=1 to infinity of cos(1/(n+1)) is diverges

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sum from n=1 to infinity of cos(1/(n+1))

n = 1 \sum \infty cos (\frac{1}{n + 1})

diverges

Solution steps

n = 1 \sum \infty cos (\frac{1}{n + 1})

Apply Series Divergence Test:

diverges

= diverges

n = 1 \sum \infty \frac{e ^{\frac{5}{n}}}{n}

n = 1 \sum \infty \frac{10}{n ^{8} + 3}

n = 1 \sum \infty \frac{3}{5 ^{n - 1}}

n = 1 \sum \infty \frac{1}{9 + e ^{- n}}

n = 2 \sum \infty (- 0.5)^{n}

What is the sum from n=1 to infinity of cos(1/(n+1)) ?
The sum from n=1 to infinity of cos(1/(n+1)) is diverges