What is the limit as x approaches-1 of x-1/(ln|x|) ?

The limit as x approaches-1 of x-1/(ln|x|) is diverges

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limit as x approaches-1 of x-1/(ln|x|)

x \to - 1 lim (x - \frac{1}{ln ∣ x ∣})

diverges

Solution steps

x \to - 1 lim (x - \frac{1}{ln ∣ x ∣})

x \to a - lim f (x) \neq = x \to a + lim f (x)

then the limit does not exist

x \to - 1 + lim (x - \frac{1}{ln ∣ x ∣}) = \infty

x \to - 1 - lim (x - \frac{1}{ln ∣ x ∣}) = - \infty

= diverges

\frac{d y}{d x} - 2 y = x^{2} e^{2 x}

f (x) = 4 sin^{2} (5 x + 3)

\int_{3}^{8} \frac{x}{x ^{2} + 6 x + 13} d x

(12 y^{2} t^{2} + 10 y) d y + (8 y^{3} t) d t = 0

f (x) = 11 x

What is the limit as x approaches-1 of x-1/(ln|x|) ?
The limit as x approaches-1 of x-1/(ln|x|) is diverges