What is the sum from n=1 to infinity of 1/(n^{0.6)} ?

The sum from n=1 to infinity of 1/(n^{0.6)} is diverges

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sum from n=1 to infinity of 1/(n^{0.6)}

n = 1 \sum \infty \frac{1}{n ^{0.6}}

diverges

Solution steps

n = 1 \sum \infty \frac{1}{n ^{0.6}}

Apply p-Series Test:

diverges

= diverges

n = 1 \sum \infty \frac{n}{2 ^{n + 1}}

n = 4 \sum \infty n e^{- n^{2}}

n = 0 \sum \infty - \frac{1}{n}

n = 0 \sum \infty cos (\frac{nπ}{2})

n = 0 \sum \infty [7 (0.1)^{n}]

What is the sum from n=1 to infinity of 1/(n^{0.6)} ?
The sum from n=1 to infinity of 1/(n^{0.6)} is diverges