What is the sum from n=1 to infinity of 1/(1+0.5^n) ?

The sum from n=1 to infinity of 1/(1+0.5^n) is diverges

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sum from n=1 to infinity of 1/(1+0.5^n)

n = 1 \sum \infty \frac{1}{1 + 0. 5 ^{n}}

diverges

Solution steps

n = 1 \sum \infty \frac{1}{1 + 0. 5 ^{n}}

Apply Series Divergence Test:

diverges

= diverges

n = 0 \sum \infty \frac{1}{1 - 2 n}

n = 0 \sum \infty \frac{3}{n ^{2} + 3 n + 2}

n = 1 \sum \infty 4 (\frac{1}{3})^{n - 1}

n = 1 \sum \infty 3 n^{2} e^{- n^{3}}

n = 1 \sum \infty [53 (\frac{1}{2})^{n}]

What is the sum from n=1 to infinity of 1/(1+0.5^n) ?
The sum from n=1 to infinity of 1/(1+0.5^n) is diverges