What is area y=2x^3-9x,y=3x^2-10 ?

The answer to area y=2x^3-9x,y=3x^2-10 is 999/32

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area y=2x^3-9x,y=3x^2-10

area

y = 2 x^{3} - 9 x, y = 3 x^{2} - 10

\frac{999}{32}

Decimal Notation

31.21875

Solution steps

Apply the area formula:

\int_{- 2}^{\frac{5}{2}} 2 x^{3} - 9 x - (3 x^{2} - 10) d x

Solve

\int_{- 2}^{\frac{5}{2}} 2 x^{3} - 9 x - (3 x^{2} - 10) d x : \frac{999}{32}

The area is:

= \frac{999}{32}

y^{^{''}} - 2 y^{^{'}} + 5 y = e^{x} cos (2 x)

\frac{d}{d x} (cos (3 x + 1))

\frac{d}{d x} (x 3 - x)

\frac{\partial}{\partial x} (- 3 x e^{2 x y})

\frac{d y}{d x} = x (8 - y)

What is area y=2x^3-9x,y=3x^2-10 ?
The answer to area y=2x^3-9x,y=3x^2-10 is 999/32