What is the sum from n=0 to infinity of (n+1)/(n+2) ?

The sum from n=0 to infinity of (n+1)/(n+2) is diverges

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sum from n=0 to infinity of (n+1)/(n+2)

n = 0 \sum \infty \frac{n + 1}{n + 2}

diverges

Solution steps

n = 0 \sum \infty \frac{n + 1}{n + 2}

Apply Series Divergence Test:

diverges

= diverges

n = 3 \sum \infty \frac{sin ( nπ )}{n}

n = 1 \sum \infty 4^{- 3 n}

k = 0 \sum \infty e^{- k}

n = 0 \sum \infty \frac{3}{5 - n}

n = 2 \sum \infty \frac{4}{n ln ( n )}

What is the sum from n=0 to infinity of (n+1)/(n+2) ?
The sum from n=0 to infinity of (n+1)/(n+2) is diverges