What is the sum from n=0 to infinity of ln(5-n) ?

The sum from n=0 to infinity of ln(5-n) is diverges

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sum from n=0 to infinity of ln(5-n)

n = 0 \sum \infty ln (5 - n)

diverges

Solution steps

n = 6 \sum \infty ln (5 - n)

Apply Series Divergence Test:

diverges

= diverges

n = 1 \sum \infty \frac{1}{2 + e ^{- n}}

n = 1 \sum \infty \frac{2}{4 ^{n}}

n = 0 \sum \infty \frac{6 ^{n}}{n !}

n = 1 \sum \infty n^{2} e^{- 2 n}

n = 1 \sum \infty \frac{1}{2 ^{n} + 3 n}

What is the sum from n=0 to infinity of ln(5-n) ?
The sum from n=0 to infinity of ln(5-n) is diverges