What is the sum from n=0 to infinity of (7/6)^n ?

The sum from n=0 to infinity of (7/6)^n is diverges

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sum from n=0 to infinity of (7/6)^n

n = 0 \sum \infty (\frac{7}{6})^{n}

diverges

Solution steps

n = 0 \sum \infty (\frac{7}{6})^{n}

Apply Series Geometric Test:

diverges

= diverges

n = 1 \sum \infty \frac{1}{3 n ^{2}}

k = 0 \sum \infty (\frac{1}{4})^{k}

n = 0 \sum \infty \frac{5}{n}

n = 1 \sum \infty \frac{8}{5 n + 12}

n = 0 \sum \infty \frac{2}{9 ^{n}}

What is the sum from n=0 to infinity of (7/6)^n ?
The sum from n=0 to infinity of (7/6)^n is diverges