What is (\partial)/(\partial x)(y^2-4x) ?

The answer to (\partial)/(\partial x)(y^2-4x) is -4

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(\partial)/(\partial x)(y^2-4x)

\frac{\partial}{\partial x} (y^{2} - 4 x)

- 4

Solution steps

\frac{\partial}{\partial x} (y^{2} - 4 x)

Treat

y

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial x} (y^{2}) - \frac{\partial}{\partial x} (4 x)

\frac{\partial}{\partial x} (y^{2}) = 0

\frac{\partial}{\partial x} (4 x) = 4

= 0 - 4

Simplify

= - 4

\frac{d}{d x} (\frac{x ^{3}}{1 + x ^{2}})

\int \frac{x ^{2} - 4}{4 x} d x

n = 0 \sum \infty \frac{n + 1}{2 n - 3}

\int \frac{2 x - 2}{1 + ( x - 1 ) ^{2}} d x

\frac{d x}{d t} = 7 (x^{2} + 1), x (\frac{π}{4}) = 1

What is (\partial)/(\partial x)(y^2-4x) ?
The answer to (\partial)/(\partial x)(y^2-4x) is -4