Solution

Solution

Solution steps
Apply the constant multiplication rule:
Apply Series Geometric Test:
Simplify

Popular Examples

sum from n=1 to infinity of 1/(3+e^{-n)}sum from n=1 to infinity of (99)/(100^n)sum from n=2 to infinity of (n-1)(1/2)^nsum from n=3 to infinity of n^2e^{-n^3}sum from n=1 to infinity of (n+1)/(n2^n)

Frequently Asked Questions (FAQ)

  • What is the sum from n=0 to infinity of 5(-2/3)^n ?

    The sum from n=0 to infinity of 5(-2/3)^n is 3