What is the sum from n=0 to infinity of (-6/7)^n ?

The sum from n=0 to infinity of (-6/7)^n is 7/13

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sum from n=0 to infinity of (-6/7)^n

n = 0 \sum \infty (- \frac{6}{7})^{n}

\frac{7}{13}

Solution steps

n = 0 \sum \infty (- \frac{6}{7})^{n}

Apply Series Geometric Test:

\frac{7}{13}

= \frac{7}{13}

n = 1 \sum \infty 90 (0.1)^{n}

i = 1 \sum \infty \frac{1}{i} - \frac{1}{i + 1}

n = 1 \sum \infty \frac{1}{5 + e ^{- n}}

m = 1 \sum \infty \frac{10}{m ^{8} + 3}

n = 1 \sum \infty 2 ln (\frac{n}{n + 1})

What is the sum from n=0 to infinity of (-6/7)^n ?
The sum from n=0 to infinity of (-6/7)^n is 7/13