What is the derivative of x^4-3x^2+4 ?

The derivative of x^4-3x^2+4 is 4x^3-6x

What is the first derivative of x^4-3x^2+4 ?

The first derivative of x^4-3x^2+4 is 4x^3-6x

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\frac{d}{d x} (x^{4} - 3 x^{2} + 4)

4 x^{3} - 6 x

Solution steps

\frac{d}{d x} (x^{4} - 3 x^{2} + 4)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x^{4}) - \frac{d}{d x} (3 x^{2}) + \frac{d}{d x} (4)

\frac{d}{d x} (x^{4}) = 4 x^{3}

\frac{d}{d x} (3 x^{2}) = 6 x

\frac{d}{d x} (4) = 0

= 4 x^{3} - 6 x + 0

Simplify

= 4 x^{3} - 6 x

\int x (x - 1) (x - 2) d x

y = (2 x^{2} - 3)^{2}

\int_{1}^{9} 4 x d x

\int \frac{1}{tan ( x ) + sin ( x )} d x

x \to 1 + lim (\frac{2}{x ^{3} - 1})

What is the derivative of x^4-3x^2+4 ?
The derivative of x^4-3x^2+4 is 4x^3-6x
What is the first derivative of x^4-3x^2+4 ?
The first derivative of x^4-3x^2+4 is 4x^3-6x