What is the sum from n=1 to infinity of cos((16)/n) ?

The sum from n=1 to infinity of cos((16)/n) is diverges

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sum from n=1 to infinity of cos((16)/n)

n = 1 \sum \infty cos (\frac{16}{n})

diverges

Solution steps

n = 1 \sum \infty cos (\frac{16}{n})

Apply Series Divergence Test:

diverges

= diverges

n = 1 \sum \infty \frac{1}{n ^{4} + 2 n + 8}

n = 0 \sum \infty \frac{n}{n + 4}

n = 0 \sum \infty \frac{3}{n ( n + 2 )}

n = 1 \sum \infty \frac{7}{n ^{2} + 64}

n = 2 \sum \infty \frac{- 2}{n ^{2} + n}

What is the sum from n=1 to infinity of cos((16)/n) ?
The sum from n=1 to infinity of cos((16)/n) is diverges