What is the sum from n=2 to infinity of nsin((10)/n) ?

The sum from n=2 to infinity of nsin((10)/n) is diverges

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sum from n=2 to infinity of nsin((10)/n)

n = 2 \sum \infty n sin (\frac{10}{n})

diverges

Solution steps

n = 2 \sum \infty n sin (\frac{10}{n})

Apply Series Divergence Test:

diverges

= diverges

n = 1 \sum \infty (\frac{3}{π})^{n}

n = 1 \sum \infty n \cdot (\frac{1}{2})^{n}

n = 1 \sum \infty \frac{1}{3 + 4 ^{- n}}

k = 1 \sum \infty 5 (- \frac{1}{6})^{5 k}

n = 1 \sum \infty \frac{3}{n ^{3} + 7}

What is the sum from n=2 to infinity of nsin((10)/n) ?
The sum from n=2 to infinity of nsin((10)/n) is diverges