What is the sum from n=0 to infinity of (2^n)/n ?

The sum from n=0 to infinity of (2^n)/n is diverges

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sum from n=0 to infinity of (2^n)/n

n = 0 \sum \infty \frac{2 ^{n}}{n}

diverges

Solution steps

n = 1 \sum \infty \frac{2 ^{n}}{n}

Apply Series Ratio Test:

diverges

= diverges

i = 1 \sum \infty 2 (\frac{4}{i})^{3} + 9

n = 1 \sum \infty \frac{1}{n} (\frac{4}{5})^{n}

n = 1 \sum \infty cos (\frac{9}{n})

n = 3 \sum \infty ln (1 + \frac{1}{n})

n = 2 \sum \infty \frac{6}{n ln ( n )}

What is the sum from n=0 to infinity of (2^n)/n ?
The sum from n=0 to infinity of (2^n)/n is diverges