What is the sum from n=0 to infinity of 1/(n^{1.5)} ?

The sum from n=0 to infinity of 1/(n^{1.5)} is converges

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sum from n=0 to infinity of 1/(n^{1.5)}

n = 0 \sum \infty \frac{1}{n ^{1.5}}

converges

Solution steps

n = 1 \sum \infty \frac{1}{n ^{1.5}}

Apply p-Series Test:

converges

= converges

n = 1 \sum \infty \frac{9}{n ^{2} + 49}

n = 0 \sum \infty 3 (\frac{4}{5})^{n}

n = 0 \sum \infty (- 1)^{n} n^{2}

k = 1 \sum \infty \frac{k !}{( 2 k ) !}

n = 1 \sum \infty (\frac{- e}{π})^{n}

What is the sum from n=0 to infinity of 1/(n^{1.5)} ?
The sum from n=0 to infinity of 1/(n^{1.5)} is converges