What is the sum from n=0 to infinity of 6/n ?

The sum from n=0 to infinity of 6/n is diverges

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sum from n=0 to infinity of 6/n

n = 0 \sum \infty \frac{6}{n}

diverges

Solution steps

n = 1 \sum \infty \frac{6}{n}

Apply the constant multiplication rule:

\sum c \cdot a_{n} = c \cdot \sum a_{n}

= 6 \cdot n = 1 \sum \infty \frac{1}{n}

Apply Cauchy's Convergence Condition:

diverges

= 6 diverges

= diverges

n = 1 \sum \infty n (\frac{5}{6})^{n}

n = 7 \sum \infty \frac{1}{n ^{2} - 5 n + 6}

n = 1 \sum \infty \frac{5}{n ^{9}}

n = 3 \sum \infty (\frac{1}{2})^{n}

n = 1 \sum \infty \frac{1}{( 6 n ) ^{6}}

What is the sum from n=0 to infinity of 6/n ?
The sum from n=0 to infinity of 6/n is diverges