What is the integral of (sec(x))/(tan(x)+cot(x)) ?

The integral of (sec(x))/(tan(x)+cot(x)) is -cos(x)+C

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integral of (sec(x))/(tan(x)+cot(x))

\int \frac{sec ( x )}{tan ( x ) + cot ( x )} d x

- cos (x) + C

Solution steps

\int \frac{sec ( x )}{tan ( x ) + cot ( x )} d x

Simplify

\frac{sec ( x )}{tan ( x ) + cot ( x )} : sin (x)

= \int sin (x) d x

Use the common integral:

\int sin (x) d x = - cos (x)

= - cos (x)

Add a constant to the solution

= - cos (x) + C

\int 4 x - 2 x^{2} d x

\int a^{(3 x + 3)} d x

y^{'} = y (3 - y) - \frac{9}{4}

y = \frac{( 3 x ^{2} + 4 ) ( 2 x + 1 )}{5 x - 9}

What is the integral of (sec(x))/(tan(x)+cot(x)) ?
The integral of (sec(x))/(tan(x)+cot(x)) is -cos(x)+C