What is the sum from n=0 to infinity of (1+2/(5n))^n ?

The sum from n=0 to infinity of (1+2/(5n))^n is diverges

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sum from n=0 to infinity of (1+2/(5n))^n

n = 0 \sum \infty (1 + \frac{2}{5 n})^{n}

diverges

Solution steps

n = 1 \sum \infty (1 + \frac{2}{5 n})^{n}

Apply Series Divergence Test:

diverges

= diverges

n = 1 \sum \infty \frac{n}{2 n ^{2} - 3}

n = 0 \sum \infty (\frac{7}{9})^{n}

n = 0 \sum \infty \frac{( n + 1 )}{n}

k = 1 \sum \infty k e^{- 6 k^{2}}

n = 2 \sum \infty \frac{1}{n} - \frac{1}{n + 2}

What is the sum from n=0 to infinity of (1+2/(5n))^n ?
The sum from n=0 to infinity of (1+2/(5n))^n is diverges