What is the sum from n=0 to infinity of n/(1+n) ?

The sum from n=0 to infinity of n/(1+n) is diverges

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sum from n=0 to infinity of n/(1+n)

n = 0 \sum \infty \frac{n}{1 + n}

diverges

Solution steps

n = 0 \sum \infty \frac{n}{1 + n}

Apply Series Divergence Test:

diverges

= diverges

x = 0 \sum \infty \frac{x ^{x}}{x !}

n = 0 \sum \infty \frac{n}{n ^{2} + 3}

k = 1 \sum \infty \frac{4}{k ( k + 2 )}

n = 1 \sum \infty 7 (0.5)^{n - 1}

n = 2 \sum \infty \frac{4}{5 ^{n}}

What is the sum from n=0 to infinity of n/(1+n) ?
The sum from n=0 to infinity of n/(1+n) is diverges