What is the sum from n=0 to infinity of ln(4n+1) ?

The sum from n=0 to infinity of ln(4n+1) is diverges

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sum from n=0 to infinity of ln(4n+1)

n = 0 \sum \infty ln (4 n + 1)

diverges

Solution steps

n = 0 \sum \infty ln (4 n + 1)

Apply Series Divergence Test:

diverges

= diverges

n = 1 \sum \infty n \cdot e^{- n}

n = 0 \sum \infty \frac{5}{n + 1}

n = 0 \sum \infty \frac{2}{5 - n}

n = 1 \sum \infty \frac{n ^{n}}{2 ^{n}}

n = 0 \sum \infty sin (\frac{πn}{4})

What is the sum from n=0 to infinity of ln(4n+1) ?
The sum from n=0 to infinity of ln(4n+1) is diverges