What is area f(x)=3x^2,g(x)=-3x+6,[-4,2] ?

The answer to area f(x)=3x^2,g(x)=-3x+6,[-4,2] is 45

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area f(x)=3x^2,g(x)=-3x+6,[-4,2]

area

f (x) = 3 x^{2}, g (x) = - 3 x + 6, [- 4, 2]

45

Solution steps

Apply the area formula:

\int_{- 4}^{2} 3 x^{2} - (- 3 x + 6) d x

Solve

\int_{- 4}^{2} 3 x^{2} - (- 3 x + 6) d x : 45

The area is:

= 45

4 e^{x} - 3 x^{2}

x \to 48 lim (\frac{x ^{2}}{8} - \frac{6}{x})

\int x^{2} \cdot e^{4 x} d x

f (x) = \frac{1}{x + 2}, at x = 9

x^{s i n (x)}

What is area f(x)=3x^2,g(x)=-3x+6,[-4,2] ?
The answer to area f(x)=3x^2,g(x)=-3x+6,[-4,2] is 45