What is the sum from n=0 to infinity of (e^n)/(n+1) ?

The sum from n=0 to infinity of (e^n)/(n+1) is diverges

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sum from n=0 to infinity of (e^n)/(n+1)

n = 0 \sum \infty \frac{e ^{n}}{n + 1}

diverges

Solution steps

n = 0 \sum \infty \frac{e ^{n}}{n + 1}

Apply Series Ratio Test:

diverges

= diverges

n = 1 \sum \infty \frac{( e ^{\frac{1}{n}} )}{n}

n = 1 \sum \infty \frac{1}{n ln ( n ^{2} )}

n = 0 \sum \infty \frac{3 n}{n + 2}

n = 1 \sum \infty (cos (9))^{n}

n = 1 \sum \infty \frac{1}{n + 2 ^{n}}

What is the sum from n=0 to infinity of (e^n)/(n+1) ?
The sum from n=0 to infinity of (e^n)/(n+1) is diverges