What is the sum from n=1 to infinity of 1/(11^n) ?

The sum from n=1 to infinity of 1/(11^n) is 1/10

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sum from n=1 to infinity of 1/(11^n)

n = 1 \sum \infty \frac{1}{1 1 ^{n}}

\frac{1}{10}

Solution steps

n = 1 \sum \infty \frac{1}{1 1 ^{n}}

n = k \sum \infty (a_{n}) = n = 0 \sum \infty (a_{n}) - a_{0} - a_{1} - \dots a_{k - 1}

= n = 0 \sum \infty \frac{1}{1 1 ^{n}} - \frac{1}{1 1 ^{0}}

n = 0 \sum \infty \frac{1}{1 1 ^{n}} = \frac{11}{10}

= \frac{11}{10} - \frac{1}{1 1 ^{0}}

Simplify

\frac{11}{10} - \frac{1}{1 1 ^{0}} : \frac{1}{10}

= \frac{1}{10}

n = 0 \sum \infty \frac{- 1 ^{n}}{n}

n = 1 \sum \infty \frac{6}{n ^{\frac{4}{3}}}

n = 0 \sum \infty \frac{n !}{n ! + 1}

k = 1 \sum \infty 5 (- \frac{1}{8})^{5 k}

n = 1 \sum \infty 5 (0.3)^{n - 1}

What is the sum from n=1 to infinity of 1/(11^n) ?
The sum from n=1 to infinity of 1/(11^n) is 1/10