What is the sum from n=3 to infinity of (n-1)/(2n+1) ?

The sum from n=3 to infinity of (n-1)/(2n+1) is diverges

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sum from n=3 to infinity of (n-1)/(2n+1)

n = 3 \sum \infty \frac{n - 1}{2 n + 1}

diverges

Solution steps

n = 3 \sum \infty \frac{n - 1}{2 n + 1}

Apply Series Divergence Test:

diverges

= diverges

n = 2 \sum \infty (\frac{2}{5})^{2 n}

n = 1 \sum \infty \frac{2 n - 1}{2 n}

n = 1 \sum \infty \frac{1}{8 n}

n = 1 \sum \infty \frac{5 n}{n ^{2} + 9}

n = 1 \sum \infty \frac{1}{( 2 n ) ^{2}}

What is the sum from n=3 to infinity of (n-1)/(2n+1) ?
The sum from n=3 to infinity of (n-1)/(2n+1) is diverges