What is the sum from n=1 to infinity of (5^n)/(2n-1) ?

The sum from n=1 to infinity of (5^n)/(2n-1) is diverges

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

sum from n=1 to infinity of (5^n)/(2n-1)

n = 1 \sum \infty \frac{5 ^{n}}{2 n - 1}

diverges

Solution steps

n = 1 \sum \infty \frac{5 ^{n}}{2 n - 1}

Apply Series Ratio Test:

diverges

= diverges

k = 0 \sum \infty (- \frac{5}{6})^{k}

n = 1 \sum \infty (\frac{1}{100})^{n}

n = 0 \sum \infty \frac{n}{n ^{3}}

n = 6 \sum \infty ln (\frac{n}{3})

n = 1 \sum \infty e^{\frac{1}{n ^{2}}}

What is the sum from n=1 to infinity of (5^n)/(2n-1) ?
The sum from n=1 to infinity of (5^n)/(2n-1) is diverges