What is the sum from n=0 to infinity of 1/((1+n)) ?

The sum from n=0 to infinity of 1/((1+n)) is diverges

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

sum from n=0 to infinity of 1/((1+n))

n = 0 \sum \infty \frac{1}{( 1 + n )}

diverges

Solution steps

n = 0 \sum \infty \frac{1}{1 + n}

Apply Series Limit Comparison Test:

diverges

= diverges

n = 0 \sum \infty cos (\frac{3}{n ^{2}})

n = 2 \sum \infty \frac{1}{( n ln ( n ) )}

n = 1 \sum \infty \frac{4}{n ^{2} + n}

n = 1 \sum \infty \frac{4 n}{4 n + 1}

n = 0 \sum \infty \frac{5}{2 n - 3}

What is the sum from n=0 to infinity of 1/((1+n)) ?
The sum from n=0 to infinity of 1/((1+n)) is diverges