What is the sum from n=0 to infinity of (-1)^{n-1} ?

The sum from n=0 to infinity of (-1)^{n-1} is diverges

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sum from n=0 to infinity of (-1)^{n-1}

n = 0 \sum \infty (- 1)^{n - 1}

diverges

Solution steps

n = 0 \sum \infty (- 1)^{n - 1}

Apply Series Divergence Test:

diverges

= diverges

n = 1 \sum \infty (9.9)^{n}

n = 1 \sum \infty 7 (0.8)^{n - 1}

n = 1 \sum \infty \frac{n}{13 n + 4}

n = 0 \sum \infty \frac{4}{5 - n}

n = 2 \sum \infty \frac{n}{n ^{2} - 1}

What is the sum from n=0 to infinity of (-1)^{n-1} ?
The sum from n=0 to infinity of (-1)^{n-1} is diverges