What is the sum from n=1 to infinity of (11^n)/n ?

The sum from n=1 to infinity of (11^n)/n is diverges

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sum from n=1 to infinity of (11^n)/n

n = 1 \sum \infty \frac{1 1 ^{n}}{n}

diverges

Solution steps

n = 1 \sum \infty \frac{1 1 ^{n}}{n}

Apply Series Ratio Test:

diverges

= diverges

n = 0 \sum \infty 8 e^{- n}

n = 2 \sum \infty (- 0.1)^{n}

n = 0 \sum \infty (\frac{4}{3})^{- n}

n = 1 \sum \infty \frac{( ln ( n ) )}{n}

n = 0 \sum \infty \frac{- 1}{n}

What is the sum from n=1 to infinity of (11^n)/n ?
The sum from n=1 to infinity of (11^n)/n is diverges