What is the sum from n=1 to infinity of ((5pi)/6)^n ?

The sum from n=1 to infinity of ((5pi)/6)^n is diverges

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

sum from n=1 to infinity of ((5pi)/6)^n

n = 1 \sum \infty (\frac{5 π}{6})^{n}

diverges

Solution steps

n = 1 \sum \infty (\frac{5 π}{6})^{n}

Apply Series Ratio Test:

diverges

= diverges

k = 1 \sum \infty \frac{5}{k}

n = 0 \sum \infty \frac{1}{6 - n}

n = 1 \sum \infty 6^{\frac{1}{n}}

n = 1 \sum \infty 6 (0.8)^{n - 1}

What is the sum from n=1 to infinity of ((5pi)/6)^n ?
The sum from n=1 to infinity of ((5pi)/6)^n is diverges