What is the sum from n=0 to infinity of sin(n/2) ?

The sum from n=0 to infinity of sin(n/2) is diverges

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sum from n=0 to infinity of sin(n/2)

n = 0 \sum \infty sin (\frac{n}{2})

diverges

Solution steps

n = 0 \sum \infty sin (\frac{n}{2})

Apply Series Divergence Test:

diverges

= diverges

n = 0 \sum \infty \frac{1}{1 - 3 n}

n = 1 \sum \infty n^{4} e^{n^{5}}

n = 1 \sum \infty \frac{2 + cos ( n )}{n}

n = 1 \sum \infty (ln (1.6))^{n}

n = 0 \sum \infty \frac{n}{7 + n}

What is the sum from n=0 to infinity of sin(n/2) ?
The sum from n=0 to infinity of sin(n/2) is diverges