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Popular >

integral from-1 to 1 of (6x^5+3)

Solution

\int_{- 1}^{1} (6 x^{5} + 3) d x

Solution

6

Solution steps

\int_{- 1}^{1} 6 x^{5} + 3 d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{- 1}^{1} 6 x^{5} d x + \int_{- 1}^{1} 3 d x

\int_{- 1}^{1} 6 x^{5} d x = 0

\int_{- 1}^{1} 3 d x = 6

= 0 + 6

Simplify

= 6

Popular Examples

derivative of y=(9x)/(e^x)derivative of

y = \frac{9 x}{e ^{x}}

f(x)=(x+1)/(x^2+1)

f (x) = \frac{x + 1}{x ^{2} + 1}

\frac{d y}{d x} - 3 y = 2

integral of 1/((x^2-9))

\int \frac{1}{( x ^{2} - 9 )} d x

integral of 3(3x+4)5

\int 3 (3 x + 4) 5 d x

Frequently Asked Questions (FAQ)

What is the integral from-1 to 1 of (6x^5+3) ?
The integral from-1 to 1 of (6x^5+3) is 6