What is the sum from g=1 to infinity of g^{gx} ?

The sum from g=1 to infinity of g^{gx} is diverges

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sum from g=1 to infinity of g^{gx}

g = 1 \sum \infty g^{gx}

diverges

Solution steps

n = 1 \sum \infty n^{n x}

Apply Series Divergence Test:

diverges

= diverges

n = 1 \sum \infty \frac{4}{n ^{2} - 4}

n = 0 \sum \infty \frac{i ^{2 n}}{n}

n = 2 \sum \infty (- 0.9)^{n}

n = 1 \sum \infty \frac{n !}{2 n}

n = 1 \sum \infty n^{- 0.6}

What is the sum from g=1 to infinity of g^{gx} ?
The sum from g=1 to infinity of g^{gx} is diverges