What is the sum from n=1 to infinity of 1/(4n+4) ?

The sum from n=1 to infinity of 1/(4n+4) is diverges

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sum from n=1 to infinity of 1/(4n+4)

n = 1 \sum \infty \frac{1}{4 n + 4}

diverges

Solution steps

n = 1 \sum \infty \frac{1}{4 n + 4}

Apply Series Integral Test:

diverges

= diverges

n = n = 1 \sum \infty \frac{1}{2 ^{n}}

k = 0 \sum \infty (\frac{3}{4})^{k}

n = 1 \sum \infty (1 - \frac{2}{n})^{3 n}

n = 6 \sum \infty \frac{2}{n - 5}

n = 0 \sum \infty \frac{1}{e ^{- n}}

What is the sum from n=1 to infinity of 1/(4n+4) ?
The sum from n=1 to infinity of 1/(4n+4) is diverges