en

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

derivative of \sqrt[4]{x}-4/x

Solution

Solution

\frac{x ^{2} + 16 x ^{\frac{3}{4}}}{4 x ^{\frac{11}{4}}}

Solution steps

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

\frac{d}{d x} (\frac{4}{x}) = - \frac{4}{x ^{2}}

= \frac{1}{4 x ^{\frac{3}{4}}} - (- \frac{4}{x ^{2}})

Simplify

\frac{1}{4 x ^{\frac{3}{4}}} - (- \frac{4}{x ^{2}}) : \frac{x ^{2} + 16 x ^{\frac{3}{4}}}{4 x ^{\frac{11}{4}}}

= \frac{x ^{2} + 16 x ^{\frac{3}{4}}}{4 x ^{\frac{11}{4}}}

Popular Examples

\frac{d y}{d x} - 2 y = 0

y^{''}+4y^'+3y=3x+7

y^{^{''}} + 4 y^{^{'}} + 3 y = 3 x + 7

integral of sin^3(xco)s^7x

\int sin^{3} (x co) s^{7} x d x

(cos(6x))y^'+6(tan(6x))y=-sec(6x)

(cos (6 x)) y^{^{'}} + 6 (tan (6 x)) y = - sec (6 x)

(\partial)/(\partial x)((2x)/((x-y)^2))

\frac{\partial}{\partial x} (\frac{2 x}{( x - y ) ^{2}})

Frequently Asked Questions (FAQ)

What is the derivative of \sqrt[4]{x}-4/x ?
The derivative of \sqrt[4]{x}-4/x is (x^2+16x^{3/4})/(4x^{11/4)}
What is the first derivative of \sqrt[4]{x}-4/x ?
The first derivative of \sqrt[4]{x}-4/x is (x^2+16x^{3/4})/(4x^{11/4)}