Solution
Solution
Solution steps
Apply Telescoping Series Test:
Popular Examples
sum from n=1 to infinity of 3(0.1)^{n-1}sum from n=1 to infinity of 6(0.4)^{n-1}sum from n=2 to infinity of 9/(nln(n))sum from n=0 to infinity of (-7/9)^nsum from n=0 to infinity of ln(1+n^2)
Frequently Asked Questions (FAQ)
What is the sum from k=1 to infinity of 1/(k^2+5k+6) ?
The sum from k=1 to infinity of 1/(k^2+5k+6) is 1/3