What is the sum from n=1 to infinity of cos^n(5) ?

The sum from n=1 to infinity of cos^n(5) is converges

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sum from n=1 to infinity of cos^n(5)

n = 1 \sum \infty cos^{n} (5)

converges

Solution steps

n = 1 \sum \infty cos^{n} (5)

n = k \sum \infty (a_{n}) = n = 0 \sum \infty (a_{n}) - a_{0} - a_{1} - \dots a_{k - 1}

= n = 0 \sum \infty cos^{n} (5) - cos^{0} (5)

n = 0 \sum \infty cos^{n} (5) =

converges

= converges - cos^{0} (5)

= converges

k = 1 \sum \infty (\frac{2}{5})^{k}

n = 5 \sum \infty \frac{1}{ln ( n - 3 )}

n = 1 \sum \infty n (\frac{1}{2})^{n - 1}

n = 0 \sum \infty \frac{5}{8 ^{n}}

n = 2 \sum \infty \frac{1}{n ^{0} ln ( n )}

What is the sum from n=1 to infinity of cos^n(5) ?
The sum from n=1 to infinity of cos^n(5) is converges