What is the sum from n=0 to infinity of (n^4)/(n+2) ?

The sum from n=0 to infinity of (n^4)/(n+2) is diverges

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sum from n=0 to infinity of (n^4)/(n+2)

n = 0 \sum \infty \frac{n ^{4}}{n + 2}

diverges

Solution steps

n = 0 \sum \infty \frac{n ^{4}}{n + 2}

Apply Series Divergence Test:

diverges

= diverges

n = 2 \sum \infty \frac{n - 1}{n !}

n = 1 \sum \infty \frac{n ^{5}}{n ^{7}}

n = 1 \sum \infty \frac{1}{ln ( 3 ^{n} )}

n = 1 \sum \infty \frac{1}{n + 5 ^{n}}

k = 2 \sum \infty k e^{- k^{2}}

What is the sum from n=0 to infinity of (n^4)/(n+2) ?
The sum from n=0 to infinity of (n^4)/(n+2) is diverges