What is the sum from n=0 to infinity of 1/(n^0) ?

The sum from n=0 to infinity of 1/(n^0) is diverges

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sum from n=0 to infinity of 1/(n^0)

n = 0 \sum \infty \frac{1}{n ^{0}}

diverges

Solution steps

n = 0 \sum \infty \frac{1}{n ^{0}}

Simplify

= n = 0 \sum \infty 1

Every infinite sum of a non-zero constant diverges

= diverges

n = 2 \sum \infty \frac{7}{n ( n + 1 )}

n = 0 \sum \infty 0.2 5^{n}

n = 1 \sum \infty sin^{n} (3)

n = 1 \sum \infty sin^{n} (9)

n = 1 \sum \infty \frac{5}{n ^{n}}

What is the sum from n=0 to infinity of 1/(n^0) ?
The sum from n=0 to infinity of 1/(n^0) is diverges