What is the sum from n=1 to infinity of (ln(4n))/n ?

The sum from n=1 to infinity of (ln(4n))/n is diverges

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sum from n=1 to infinity of (ln(4n))/n

n = 1 \sum \infty \frac{ln ( 4 n )}{n}

diverges

Solution steps

n = 1 \sum \infty \frac{ln ( 4 n )}{n}

Apply Series Integral Test:

diverges

= diverges

n = 1 \sum \infty \frac{3 ^{n}}{3 + n !}

n = 1 \sum \infty (\frac{4}{5})^{n - 1}

n = 0 \sum \infty arctan (3 n)

n = 2 \sum \infty \frac{1}{n} - \frac{1}{n + 1}

n = 1 \sum \infty \frac{1 6 ^{n}}{n !}

What is the sum from n=1 to infinity of (ln(4n))/n ?
The sum from n=1 to infinity of (ln(4n))/n is diverges