What is the sum from n=1 to infinity of cos(6/n) ?

The sum from n=1 to infinity of cos(6/n) is diverges

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sum from n=1 to infinity of cos(6/n)

n = 1 \sum \infty cos (\frac{6}{n})

diverges

Solution steps

n = 1 \sum \infty cos (\frac{6}{n})

Apply Series Divergence Test:

diverges

= diverges

n = 1 \sum \infty n^{\frac{1}{2}}

n = 0 \sum \infty (\frac{1}{15})^{n}

n = 1 \sum \infty \frac{7 n}{5 + 6 n}

n = 1 \sum \infty 1 + (- 1)^{n}

n = 1 \sum \infty \frac{n ^{3}}{8 ^{n}}

What is the sum from n=1 to infinity of cos(6/n) ?
The sum from n=1 to infinity of cos(6/n) is diverges