What is the sum from n=1 to infinity of 1/(2n+2) ?

The sum from n=1 to infinity of 1/(2n+2) is diverges

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sum from n=1 to infinity of 1/(2n+2)

n = 1 \sum \infty \frac{1}{2 n + 2}

diverges

Solution steps

n = 1 \sum \infty \frac{1}{2 n + 2}

Apply Series Integral Test:

diverges

= diverges

n = 0 \sum \infty \frac{5}{0. 5 ^{n} - 2}

n = 0 \sum \infty \frac{2 ^{n}}{n ^{7}}

k = 2 \sum \infty (\frac{2}{3})^{3 k}

n = 1 \sum \infty n! e^{- 4 n}

n = 1 \sum \infty \frac{8 n}{8 n + 1}

What is the sum from n=1 to infinity of 1/(2n+2) ?
The sum from n=1 to infinity of 1/(2n+2) is diverges