What is the sum from n=1 to infinity of (7^n)/(n+1) ?

The sum from n=1 to infinity of (7^n)/(n+1) is diverges

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sum from n=1 to infinity of (7^n)/(n+1)

n = 1 \sum \infty \frac{7 ^{n}}{n + 1}

diverges

Solution steps

n = 1 \sum \infty \frac{7 ^{n}}{n + 1}

Apply Series Ratio Test:

diverges

= diverges

n = 0 \sum \infty 2^{n} - n

n = 1 \sum \infty (cos (3))^{n}

n = 0 \sum \infty \frac{1}{5} (\frac{4}{5})^{n}

n = 1 \sum \infty \frac{1}{n ^{2.5}}

n = 4 \sum \infty \frac{1}{n ^{2} - 1}

What is the sum from n=1 to infinity of (7^n)/(n+1) ?
The sum from n=1 to infinity of (7^n)/(n+1) is diverges